Recent content by Ben Wood

Thanks very much, I understand it now. thanks for teaching the thought process. Ben

Yeah, I calculated it wrong by the looks of things. I've tidied up again and it's more in line with Kinggy above. Also, I have been using the ENG button to keep it uniformed to x10-6

I had a go, see what you think: -

Apologies, my top line should have been as below. The internal bore diameter has been added. 1/√(0.032) = -1.8log [ (6.9/Re) + ( (1.5x10-6 / 0.04) / 3.7)1.11 ] You were correct with the answer at the top being 3.75 x10-5 (My Bad) I had a telephone conversation with a classmate and he told me...

Hi Guys, I've just started a HND Building Services Engineering course (for Work) and I have been given my first assignment for hand in on the 11th Nov 2014. I've not completed any Maths or Physics since Secondary School - 18 years ago (and didn't really pay attention then!) and I'd appreciate...