Recent content by ben23

I'm one of the few physics majors who never took physics or calculus in high school, and am currently a senior with a 3.9 GPa. Just be ready to work hard and you should be fine. High school preparation becomes increasingly irrelevant as you progress through college.

mechanics (junior) e & m (junior) experimental physics I (of IV) astrophysics chicano studies (G.E.)

Since you want to know f(x) without all that "stuff" inside the parentheses, let u= 3x5. Then f(3x5)= f(u) and df/dx= (df/du)(du/dx)= (df/du)(15x)= 8x2. Now you have df/du= (8/15)x. Since u= 3x5, x5= u/3 and x= (u/3)1/5. df/du= (8/15)(u1/5)/31/5. Now just replace u by x to get f'(x) I see...

Here's the problem: d/dx(f(3x^5)) = 8x^2 Find f'(x) After applying the chain rule: f'(3x^5)(15x^4) = 8x^2 f'(3x^5) = 8/(15x^2) It's not apparent to me how I proceed from here to find f'(x). I tried dividing the expression on the right by three and taking the fifth root but that does not...