Recent content by benjamintpike

ok so that didnt go to well haha what I am thinking now is could I use PE = mgh assuming negligble losses as the ball changes its energy at the bottom of the curve. So I would now use the energy of the pin to replace the PE in PE = mgh that gives me height

thinking the angular velocity is incorrect as time is not part of the equation in that post which is important

SO does that mean that the rotational and translational energy of the ball must be equal to or greater than the potential energy of the bowling pin that I worked out earlier. so far I have worked out the Inertia of the ball to be 79.597 ok so now I think that the minimum energy would look...

as to how accurate and real life, not really just something pretty close that would give a good indication of what we needed. and yep minimum height is what we are after, just to prove mathmatically we need a height higher than it The hockey ball is because as well as hockey on ice we...

lol it is a bit confusing yes, ok hockey ball is 71mm in diameter, and on a weighing scales 157.9g or base unit of mass 0.1579Kg. skittle/Pin = 1.595Kg Point of impact I don't know that distance but can put it up on here tomorrow morning, obviously we have a time difference being...

The diagram that I forgot to put in

Hi yeah its all a bit confusing. Basically we are designing a machine that will knock a skittle down, to build it we have to meet certain requirments/constraints etc. One of those requirements is that the device we build will be one metre away from the skittle so that means that the exit of...

Yep its a bowling pin USBC standard I believe

First off I don't believe this would be classed as a homework question, as this is an engineering design project problem and I haven't been to school for over ten years, however if I am wrong I apologise. My problem is:- The object I want to knock down is a skittle: h = distance from...