Recent content by beyondthemaths

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    I Why can't Gravitational Accelerations vanish everywhere?

    I see, I still have one question then. In the question above, it is also mentioned that " This should then be interpreted as meaning that the sum of the inertial and the gravitational acceleration could be made equal to zero everywhere. " Why sum? How was this interpreted? I mean interpretation...
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    I Why can't Gravitational Accelerations vanish everywhere?

    In attempt to describe the consequences of the Equivalence Principle, this is almost said: When there are gravitational accelerations present, as for example in the gravitational field of the earth, the space cannot be the flat Minkowski space. Indeed, in the Minkowski space we can have...
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    Simplifying Tensor Equations: A Guide for Beginners

    Ok thank you a lot. I now got what you meant.
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    Simplifying Tensor Equations: A Guide for Beginners

    Do you mean that I should have derived wrt A? Well, because what I am trying to find is ##G_{\mu\nu}=\delta S/\delta F^{\mu\nu}##. The formula that I have come across in the web says so, maybe in few resources it says so, in some others, it says ##G_{\mu\nu}=\epsilon_{\mu\nu\rho\sigma}\delta...
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    Simplifying Tensor Equations: A Guide for Beginners

    Hello @fzero ! Sorry I am reviving the thread again but as I was reviewing what I learned yesterday, I am wondering about something: In this one, now in order to proceed like we did in our first case, I should lower indices in ##F^{I\rho\sigma}## right? So I can also use the ##\epsilon## for...
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    Simplifying Tensor Equations: A Guide for Beginners

    Indeed, those are what I am talking about so to cut the story short, I will continue with what we started ##\delta^{()}_{()}\delta^I_J##, safe no?
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    Simplifying Tensor Equations: A Guide for Beginners

    Then it is okay to consider the I and J and place them in a kronecker delta and this has nothing to do with the fact that they are functional or not.
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    Simplifying Tensor Equations: A Guide for Beginners

    Thank you for being very helpful. I appreciate it a lot @fzero!
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    Simplifying Tensor Equations: A Guide for Beginners

    I have one question, as I said above ##N_{IJ}## is a complex symmetric matrix, that is I do not know if we should consider ##I## and ##J## to be functional here and embed them in a Kronecker delta or should I consider them as if they were not there because those are things that span the space...
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    Simplifying Tensor Equations: A Guide for Beginners

    Oh my, what I did was terrible! I now understand this, thank you very much!
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    Simplifying Tensor Equations: A Guide for Beginners

    Hello! Thank youuu, that is what I was meaning. So, if I want to carry on from your last step, $$\frac{\delta S}{\delta F_{\lambda...
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    Simplifying Tensor Equations: A Guide for Beginners

    I guess, the question is not clear enough. My confusion is in the following, if in the least usage of words: If ##L = \frac{1}{2}N_{IJ}F_{\mu\nu}^I\tilde{F}^{J\mu\nu} ##, what is ##\delta L/\delta F^{\rho\sigma J}##?
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    Simplifying Tensor Equations: A Guide for Beginners

    No, here "I" is related to the "I" in ##N_{IJ}## which is a matrix. F is a rank 2 tensor. Suppose there were no "I" or "J" to start with, how can I derive ##1/2 N_{IJ}F_{\mu\nu}\tilde{F}^{\mu\nu} ## wrt ##F^{\rho\sigma}## meanwhile it has no ##\rho## nor ##\sigma## in it?
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    Simplifying Tensor Equations: A Guide for Beginners

    Hello, I am very new to tensors and GR and would like to ask for guidance to understand how tensor simplification works. If we have this term $$\frac{1}{2}N_{IJ}F_{\mu\nu}^I\tilde{F}^{J\mu\nu} $$ and I want to derive w.r.t ##F^{\rho\sigma I}## where - ##N_{IJ}## is a symmetric complex matrix -...
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    Find G_{\mu\nu} from Supergravity Lagrangian: Chapter 4, Section 4.3.2

    I am reading the book Supergravity. In chapter 4, section 4.3.2 - Duality for gauge fields and complex scalar: The simplest case of electromagnetic duality in an interacting field theeory occurs with one abelian gauge field ##A_{\mu}(x)## and a complex scalar field ##Z(x)##. The...
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