3 mod 10 = 3
4 mod 10 = 4
10 mod 3 = 1
10 mod 4 = 2
in Schnorr
h= -k^(-2) mod n
h= -(k^(-1))^2 mod n
Hence for 2 primes
9 mod 2 = 1
(3)^2 mod 2 = 1
Therefore k^(-1) = 3 Is this right please your opinion please - thanks in advance
Please help - I am helping a student who is trying to translate Ong-Schnorr to C++ or VB.net language. My major was electronics so I am not sure how to interpret inverse random integer k. Any one ? or suggest me a reference to read on - much thanks, newbie
Ong-Schnorr-Shamir (from Briuce's...