Recent content by bibrahim6

Nevermind I put 8.3 instead of 8.5 THANK YOU FOR THE HELP!

I corrected that and ended up getting 3299 m/s...can you lay out an exact equation please I am just not seeing my error

So this was my attempt (.5)m( (vf)^2 - (2250)^2 )= -(6.67e-11)* ( (m *6.4 × 1023 ) / (5.3e6 - 8.3e6) ) so m= mass of spacecraft I'm assuming it cancels out and i end up getting vf= 2250 which is not correct and does the radius of Mars come into play in this problem?

Ive tried delta K = delta U so 1/2 m(vf-vi)^2 = -G (Mm/(rf-ri)) but i get initial is equal to final since the potential is very small

A spacecraft is coasting toward Mars. The mass of Mars is 6.4 × 1023 kg and its radius is 3400 km (3.4 × 106 m). When the spacecraft is 8500 km (8.5 × 106 m) from the center of Mars, the spacecraft 's speed is 2250 m/s. Later, when the spacecraft is 5300 km (5.3 × 106 m) from the center...