Recent content by bilalbajwa

Hi, Thanks for replying. As i said box is oscillating up and down. And its this jumping comes to a complete rest after some time.

I am talking about the air friction.

Friction Problem. Help! Homework Statement In the absence of friction, we know v = (2gd)^(1/2). But with a correction factor that accounts for friction what would be the modified farmula? d=distance of box from the spring platform. g=acceleration due to gravity The Attempt at a...

Is this the vector diagram i am going to make http://docs.google.com/Doc?id=dctgg53g_60dsdbbn Velocity of plane relative to ground(Vpg)-Velocity of wind relative to ground(Vwg)= Velocity of plane relative to wind(Vpw)

Two dimension relative morion help! Homework Statement After flying for 15 min in a wind blowing 42 km/h at an angle of 18° south of east, an airplane pilot is over a town that is 60 km due north of the starting point. What is the speed of the airplane relative to the air? Homework...

OK i find that on internet. Thanks viewers. http://www.maths.abdn.ac.uk/~igc/tch/ma1002/int/node34.html

I need method to solve it!

Hi guys, Can anybody tell me how to integrate \int x\arctan(x) dx I have tried a lot. The condition is i don't want to use integration tables.

Because at the end of the interval Instantaneous velocity is on the peak and AVG velocity is the averages of the inital + final. (i am not sure):confused:

OK one thing i got here: SECTION I Coloumn comparison "Velocity" vs yi/ti "Velocity" = Instantaneous Velocity yi/ti = Average Velocity Conclusion: In a free falling body, when we take equal time intervals and unequal displacements. Avg Velocity is half of Instantaneous velocity...

Q1. Average Acceleration = delta x/ delta ok i understand but what is yi/ti^2? WHY yi/ti^2 is half of avg acceleration? WHats the logic comming out of it?

Free fall Experiment Help! 1. Homework Statement Experiment:- OBJECTIVES In this experiment you will investigate the motion of a freely falling body on a fictitious planet. You will discover for an object that falls from rest (1) the value of the acceleration due to gravity on the...

Thanks a lot for reply and this wonderfull equation relationship! Please be tune i am going to show u a lab experiment!

Thanks a lot guys. I get a very very very very very quick response here. Thanks a lot. :smile::smile::biggrin:

OK I think i am getting what you guys are saying: when we throw something in upward direction we can use either of these equations -s=-ut+1/2gt^2 or s=ut-1/2gt^2 Am i right!