Hi saltydog,
I tried to do it one more time and I think what happens is the outer graph is the f=1, and the inner graph is the f=0. When you plot the figure, it shows the last one (which is i=10) the first somehow and the first one (i=1) the last. You can try by individually drawing the figures...
hi saltydog,
Thnak you for the code. I couldn't manage to plot everything in one figure. How did you do that? Because when I used your code, it plotted all of the graphs separately.
I have another question. As far as I understood, you tell me that for a given b value, the higher the 'f' is...
numerical solution
It is actually ok for me to obtain a numerical solution close to zero.
However, my background in computational stuff is not very good, since I am a theorist. I just tried to do it numerically with some software (Mathematica) but couldn't do it since it says (there is...
Thanks again for your interest, saltydog.
You are right there is typo there, but the result is the same. Here is the corrected one: http://www.people.virginia.edu/~bk5w/home_files/ode2.pdf
One another thing is f is between [0,1], which means it can be zero as well (when you wrote, you...
I also what I meant by singular initial value problem is the following
my initial conditions are
z(0)=0 and z'(0)=0
However, when b=0, the differential equation I wrote before, involves division by zero, which creates a problem.
Hi saltydog. Thanks for the welcome.
Your solution way when f=1 is correct and it is true that it works when b is not 0.
Hence, I also think that the solution is not unique when b=0.
I also provided different ways of solving it when f=1. (I attached a pdf file below).
Do you know how to...
I need to solve the following second order nonlinear differential equation:
z''(b) * [6(1 - f)z(b) + (1+f)b z'(b)] = (15 - 9 f)[z'(b)]^2 + [2(1 - f) z(b) z'(b)] / b + [4 f z'(b)^(5/2)] / b^(1/2)
where f is a constant between [0,1].
initial conditions are z(0)=0 and z'(0)=0
I...