Recent content by Bix

OK. Thanks very much again for your help :smile:

If it's 1:100 then when the run is 100 the rise is 1.00. So I'm reasoning that when the run is 4 the rise is 0.04.

Hi PeroK thanks: the run is 4m so I'm finding a rise of 0.04

Thanks again for your answers FxD = 1200 (4x300) To find h in PE = mgh: Either divide one by a hundred and times by 4 = 0.04 Or Inv Tan 1/100 = 0.57 approx Adjacent side length 4m divided by Cos 0.47 = 4.0002 = length of hypotenuse H squared 16 and 1/625 minus A squared 16 = B squared B =...

Hello. Be v grateful any assistance with this. Question is energy to haul 2000kg 4 metres up a 1 in 100 incline with 300 Newtons friction Answer is given as exactly 1.98 kJ. The only figures I can see that relate to anything here are 2000kg minus 10 = 1980, and 1:100 is 0.01 which times...

Thanks guys, massively appreciated :) Interesting insight haruspex..

In answer to this I get power = force times velocity so 30000 x 50 = 1500000 = 1.5 Mega Watts. My answer book says 1.47 Mega Watts. I can see how 1.5MW minus 30KW = 1500000 - 30000 = 1.47MW. Also I can see that power times gravity of 9.8 = 1.5 MW times 9.8 N gives the same answer. I can't see...

How did you find PF?: Online [Thread moved from the New Member Intro forum, so no Schoolwork Template is shown] Hi. I'm new and am trying to solve a simple question 'Find the max power of a train engine traveling level at 50 metres per second if total resistance to motion is 30 KiloNewtons...