So basically what you're saying is that...
drop 1(coming right out of the head) is at t=0
drop 2(1st drop in air) is at .58/3= t=.19s
drop 3(2nd drop in air) is at .19*2 t=.39s
drop 4(hitting the ground) is at t=.58s
Nope, there is no figure. The only thing I'm going by the different drops is that they each drop at the same interval, but by the time the 1st drop hits the ground(.58s) the 4th drop is just now leaving the showerhead. So I figured that if I broke that down into 4 equal parts it would work, but...
Using y=(1/2)at^2
-1.65= .5(-9.8)(t^2)
(-1.65/-4.9)=t^2
sqrt(.34)=t
0.58=time
I figured out the time it took for one droplet to go from the sprinkler head to the ground... then since there was 4 droplets and it said that they were released at equal...
Water drips from the nozzle of a shower onto the floor 165 cm below. The drops fall at regular (equal) intervals of time, the first drop striking the floor at the instant the fourth drop begins to fall.
a)Find the location of the third drop as measured from the nozzle of the shower when the...