Recent content by blade_090

ok i got ur point there... is that any possible that copper has it own pressure beside the atmospheric pressure?? i found the work done from copper..its 0.443J bt it is different from the standard answer it gave (0.434J)

so far what i know about ideal gas equation is PV = nRT so i have to find the volume change for the ideal gas use it on W = P dV and i manage to find work done for ideal gas :) however i still dun have any clue about work done on copper and for compressibility: K = (-1/v)(dV/dP) im still...

Homework Statement An ideal gas, and a block of copper, have equal volume of 0.5m^3 at 300K and atmospheric pressure. The pressure on both is increased reversibly and isothermally to 5atm. Find the work done of each if the compressibility of copper is 0.7X10^-6 atm-1 the atmospheric...

1. Homework Statement [/b] 1)for an object of size 0.5 Angstrom, what is the longest-wavelength photon with which it can be observed? 2)for the object of problem 1, what is the smallest-energy electron which can be used to make the measurement? Homework Equations 1)\Deltap x \Delta x \geq...

does tat mean something wrong with the ans given?? or i should use relativistic formula since the kinetic energy of electron is larger thn rest energy of electron?

Homework Statement To "obeserve" small objects,one measures the diffraction of the particles whose de Broglie wavelength is approximately equal to the object's size. Find the kinetic energy(in electron volts) required by the electrons to resolve c) a nucleus of size 10fm. Homework...

Homework Statement what is the minimal wavelength of electromagnetic radiation to pair-produce an electron-positron pair? Homework Equations ~ = wavelength hc/~ = 2MeC^2 + K The Attempt at a Solution hc/~ = 2MeC^2 = 2(9.11x10^-31)(3x10^8)^2 ~ = 8.24x10^-11m is tis correct?

im using digital storage oscilloscope to measure the frequency of ac signal wat will happen to the frequency of ac signal if i change the coupling from ac to dc?? will there be any changes? how to explain the changes?

lolx..silly me XDD i missunderstand ur explanation jus now i figured it out.. thx for ur help ^^

i mean how do find the new length the block travelled? is the block's acceleration-----mgsin20=ma?

ic...so how do i find the distance traveled by the block? i got to find the acceleration 1st rite? thru mgsin20=ma?

1/2mv2+mglsin20=1/2kx2 1/2(2.5)(0.75)^2+2.5(9.8)(0.3sin20)=1/2(500)(x)^2 x=0.113m bt the real ans is o.131m i wonder which part i did wrong

Homework Statement an inclined plane of angle 20 degree has a spring of force constant k= 500N/m fastened securely at the bottom so that the spring is parallel to the surface. a block of mass m=2.5kg is placed on the plane at a distance d=0.300m from the spring. From this position, the block...