Recent content by blue88

I did P=(4.8E-4)(.2)(28) P= 2.688W Q=Pnet(t) Q=(2.688)(86400) Q= 232243.2 J of heat but i don't think that I am even starting it right.

The average thermal conductivity of the walls (including windows) and roof of a house in Figure P11.32 is 4.8 10-4 kW/m°C, and their average thickness is 20.0 cm. The house is heated with natural gas, with a heat of combustion (energy given off per cubic meter of gas burned) of 9300 kcal/m3...

Hi, thanks for the info. I tried using the equation, P + 1/2pv^2 = P + 1/2pv^2 and I ended up with two unknowns, the two different v^2. So then I tried solving for 1 v using the AV=AV equation and then plugging it back into the first equation but that didn't come out right either...

I have this problem: Water flowing in a horizontal pipe is at a pressure of 1.5 105 Pa at a point where its cross-sectional area is 1.50 m2. When the pipe narrows to 0.400 m2, the pressure drops to 1.16 105 Pa. (a) Find the water's speed in the wider pipe (b) Find the water's speed in the...

but i need to derive this formula: x = (sqrt of 2h/g)v from these two equations: h = .5gt^2 x = vt i still don't understand how to do that

but there is no way to combine the x=vt with it?

yes, this is the formula, it was for a lab so we were using x as a distance

I need to derive this formula: x = (sqrt of 2h/g)v from these two equations: h = .5gt^2 x = vt Thanks... just can't figure this out!