Recent content by BlueDevil14

Thanks. It all makes sense now.

for anyone else reading this thread, here is the Taylor expansion for the bracketed term (to the sixth power): -b Δr+\frac{3 b^2 Δr^2}{2}-\frac{7 b^3 Δr^3}{6}+\frac{5 b^4 Δr^4}{8}-\frac{31 b^5 Δr^5}{120}+\frac{7 b^6 Δr^6}{80}... Therefore Hooke's Law may be written as F_{r}=-AbΔr...

Thanks. Can you explain why I only keep the constant and linear terms?

I could really use some help. I am getting nowhere.

Homework Statement Many diatomic (two-atom) molecules are bound together by covalent bonds that are much stronger than the van der Waals interaction. Experiment shows that for many such molecules, the interaction can be described by a force of the form F_{r} = A[ e^{- 2b( r - R_0 )} - e^{ -...

Thanks, it sometimes just requires someone to point out the obvious for you

oh... I forgot to add the weights! then in should be P_{2}=\frac{(47.0+88) \mathrm{N}}{.071 \mathrm{ m}^3}=1901 \mathrm{ Pa} It is therefore 1901-665 not 1245-665

I was thinking the change in pressure a the bottom would be equal to the change in pressure at the top, and the final-initial at top would be 1245-665 Pa.

Homework Statement A cylindrical disk of wood weighing 47.0 N and having a diameter of 30 cm floats on a cylinder of oil of density 0.850 g/cm^3 (the figure). The cylinder of oil is 75.0 cm deep and has a diameter the same as that of the wood. a) What is the gauge pressure at the top of the...

The torque is about the pivot point, I am only using torque as an equation to solve for T

Thanks, that makes sense. For some reason though, it is not correct still. I assume it is another aimless trig mistake.

I believe the problem assumes that the rope does not pivot, as odd as that sounds. The torques are all with respect to a pivot about the climber's feet. Because gravity acts downwards, the torque will be clockwise.

Yes, I am trying to find tension in the rope. Sorry, I left out that important piece of information.

Homework Statement Mountaineers often use a rope to lower themselves down the face of a cliff (this is called rappelling). They do this with their body nearly horizontal and their feet pushing against the cliff (the figure ). Suppose that an 76.2 kg climber, who is 1.88 m tall and has a center...

Can someone please explain to me in layman's terms what a non-linear oscillator is? I need to determine if a ring pendulum is a non-linear oscillator, but I can't really do that without knowing what it is I am describing.