Recent content by BlueDevil14

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    Oscillations of Covalent Molecules

    Thanks. It all makes sense now.
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    Oscillations of Covalent Molecules

    for anyone else reading this thread, here is the Taylor expansion for the bracketed term (to the sixth power): -b Δr+\frac{3 b^2 Δr^2}{2}-\frac{7 b^3 Δr^3}{6}+\frac{5 b^4 Δr^4}{8}-\frac{31 b^5 Δr^5}{120}+\frac{7 b^6 Δr^6}{80}... Therefore Hooke's Law may be written as F_{r}=-AbΔr...
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    Oscillations of Covalent Molecules

    Thanks. Can you explain why I only keep the constant and linear terms?
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    Oscillations of Covalent Molecules

    I could really use some help. I am getting nowhere.
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    Oscillations of Covalent Molecules

    Homework Statement Many diatomic (two-atom) molecules are bound together by covalent bonds that are much stronger than the van der Waals interaction. Experiment shows that for many such molecules, the interaction can be described by a force of the form F_{r} = A[ e^{- 2b( r - R_0 )} - e^{ -...
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    Simple Fluids Problem: Cylinder on Oil with Added Weight

    Thanks, it sometimes just requires someone to point out the obvious for you
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    Simple Fluids Problem: Cylinder on Oil with Added Weight

    oh... I forgot to add the weights! then in should be P_{2}=\frac{(47.0+88) \mathrm{N}}{.071 \mathrm{ m}^3}=1901 \mathrm{ Pa} It is therefore 1901-665 not 1245-665
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    Simple Fluids Problem: Cylinder on Oil with Added Weight

    I was thinking the change in pressure a the bottom would be equal to the change in pressure at the top, and the final-initial at top would be 1245-665 Pa.
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    Simple Fluids Problem: Cylinder on Oil with Added Weight

    Homework Statement A cylindrical disk of wood weighing 47.0 N and having a diameter of 30 cm floats on a cylinder of oil of density 0.850 g/cm^3 (the figure). The cylinder of oil is 75.0 cm deep and has a diameter the same as that of the wood. a) What is the gauge pressure at the top of the...
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    How Do Climbers Use Physics to Rappel Down Cliffs?

    The torque is about the pivot point, I am only using torque as an equation to solve for T
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    How Do Climbers Use Physics to Rappel Down Cliffs?

    Thanks, that makes sense. For some reason though, it is not correct still. I assume it is another aimless trig mistake.
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    How Do Climbers Use Physics to Rappel Down Cliffs?

    I believe the problem assumes that the rope does not pivot, as odd as that sounds. The torques are all with respect to a pivot about the climber's feet. Because gravity acts downwards, the torque will be clockwise.
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    How Do Climbers Use Physics to Rappel Down Cliffs?

    Yes, I am trying to find tension in the rope. Sorry, I left out that important piece of information.
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    How Do Climbers Use Physics to Rappel Down Cliffs?

    Homework Statement Mountaineers often use a rope to lower themselves down the face of a cliff (this is called rappelling). They do this with their body nearly horizontal and their feet pushing against the cliff (the figure ). Suppose that an 76.2 kg climber, who is 1.88 m tall and has a center...
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    Non-Linear Oscillator: Understand & Determine Ring Pendulum

    Can someone please explain to me in layman's terms what a non-linear oscillator is? I need to determine if a ring pendulum is a non-linear oscillator, but I can't really do that without knowing what it is I am describing.
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