In an LCR circuit (circuit with inductor, capacitor and resistor), are the following statements always true?
The capacitor voltage always lags the resistor voltage by a phase difference of 90°.
The inductor voltage always leads the resistor voltage by a phase difference of 90°.
The current...
Sorry I should have explained it better. When you rearrange the equation, you get the x and dx on one side, and the y and dy on the other side. Do you have to make each side an integral? E.g. does it have to be ∫x dx = ∫y dy, or can you rearrange to x dx = y dy? If you can, what does the...
If you have a differential equation with variables separated, such as dy/dx = 4x2/3y3, and you rearrange it to 3y3 dy = 4x2 dx, what does the dy/dx mean in this case, and can you even rearrange it like that or must you do this: ∫3y3 dy = ∫4x2 dx ?
I never really understood leibniz notation. I know that dy/dx means differential of y with respect to x, but what do the 'd's mean? How come the second-order differential is d2y/dx2? What does that mean? And what does d/dx mean?
Homework Statement
Solve the equation √(6 + 3√2) = √a + √b, writing a and b in the form a + b√c.
Homework Equations
In the answers they say that a + b = 6, but I cannot see how they can say this.
The Attempt at a Solution
I square both sides, and that is as far as I get:
6 + 3√2 =...
Aha! So the net EMF is what creates a current in a closed circuit or part of a circuit? And the net EMF in this circuit is zero so the current will also be zero?
:D
I'm getting confused with EMF, terminal voltage and internal resistance etc... isn't the 1.5V the EMF, which means that the actual potential rise (terminal voltage) will be less that 1.5V?
If I were to add up the EMFs, I would be assuming no current is flowing.
Homework Statement
What is the current in this circuit:
http://img802.imageshack.us/img802/4646/8ekh.png [Broken]
Homework Equations
All potential differences in a closed portion of a circuit must add to 0.
Terminal Voltage = EMF - I x internal resistance.
The Attempt at a Solution
I do not...