Recent content by BondKing

  1. BondKing

    Lower Bound Iterated Integral | MATH200

    thanks bro
  2. BondKing

    Lower Bound Iterated Integral | MATH200

    Tried both ways. = (
  3. BondKing

    Lower Bound Iterated Integral | MATH200

    but y = (-5/4)x+5 is only applicable till y = 2.5 though.
  4. BondKing

    Lower Bound Iterated Integral | MATH200

    I am confused too. = ( only c is wrong.
  5. BondKing

    Lower Bound Iterated Integral | MATH200

    https://webwork.elearning.ubc.ca/webwork2_files/tmp/MATH200-ALL_2014W1//gif/G7FDHYKMT809-3725-setAssignment9prob2image1.png How can I find the lower bound for an iterated integral in this case? My attempt: y = (-5/4)x+5 (which represents the line) But it doesn't work.
  6. BondKing

    Identifying local maximum, local minimum and saddle point.

    Indicate whether you think it is a local maximum, local minimum, saddle point, or none of these? My solution: Point P = Local Max Point Q = Local Min Point R = None Point S = Saddle I got a 75% for first attempt, so one answer is not correct and I am not sure which one isn't.
  7. BondKing

    Directional derivatives and the gradient vector

    Is there a way to obtain a vector (out of many)?
  8. BondKing

    Directional derivatives and the gradient vector

    How should I approach this question? Find the directional derivative of f(x,y,z)=xz+y2 at the point (3,1,2) in the direction of a vector making an angle of −π/4 with ∇f(3,1,2). I found the gradient to be <2,2,3>
  9. BondKing

    Directional derivatives and the gradient vector

    If the unit vector u makes an angle theta with the positive x-axis then we can write u = <cos theta, sin theta> Duf(x, y) = fx(x,y) cos theta + fy(x,y) sin theta What if I am dealing with a function with three variables (x, y, z)? How can I find the directional derivative if I have been given...
  10. BondKing

    Can someone please check my logic proof?

    (c v ~ h) - > ~ m (prem 1) T -> ~ c (prem 2) T ^ h (prem 3) trying to get m 1) T (spec prem 3) 2) ~ c ( M.PON prem 2, 1) 3) ~ h (ELIM prem 1 (c v ~ h), 2) 4) ~ h - > ~ m (replace (c v ~ h) with ~h) 5) m -> h (Contrap. 4) 6) ~m v h (M.TOL 5,3) 6) m
  11. BondKing

    Time rate of change of air pressure

    -15 = ∂p/∂t + (-2.5)(10) ? Is the unit for the answer Pa/hr?
  12. BondKing

    Time rate of change of air pressure

    Air pressure decreases at a rate of 2.5 pascals per kilometer in the eastward direction. In addition, the air pressure is increasing at a constant rate with respect to time everywhere. A ship sailing eastward at 10 km/hour past an island takes barometer readings and records a pressure drop of 30...
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