Recent content by boozi

And when I'm crossing the two, I'll just need to multiply v by r and then by sin 45, right?

First, thanks for replying to my post. Second, here's what I did: vector v = 0i + 3.0*10^7j \hat{r}=-0.01/0.028i - 0.01/0.028j Now, hopefully, that's correct. With that, the only thing left to do is multiply m0/4pi * q/r, which is 2.003*10^-23 by \hat{r} and then cross it with vector v, right?

Homework Statement What are the magnetic field strength and direction at the dot in Figure Ex32.8, in which v = 3.0*10^7 m/s? Figure Ex.32.8 is attached to the this post. r = 0.02828 m m0/4pi = 10^-7 T v = 3.0*10^7 m/s q = 1.60217653*10^-19 C Homework Equations Biot-Savart Law...

ah ****... I'm stupid... thanks :P

V = partial x + partial y? Well, grad V = partial x + partial y

I'm still a bit confused... Well, I have to take into account the direction, too, but... How do I account for it in the equation?

Hello. This is my first time here, so let me know if I'm doing anything wrong "posting-wise." Homework Statement The electric potential in a region of space is V= (260 x^2 - 180 y^2) V, where x and y are in meters. What is the strength of the electric field at (2.00 m, 3.00 m) ? x =...