Recent content by bossler

Thanks a lot for the help

Alright well I'm glad to see I'm making some progress. The equation you mentioned I had forgot about, and certainly makes things a bit simpler when not having to use time. If I used that equation I would set the formula up as d=(vf^2-vo^2)/2a ,with vf^2 being 0, and vo^ being ([sqrt...

Would it work if I substituted in (vy - vyo)/g for t? If I did that it would be ((([sqrt (19.62(H-L*sin theta))] * sin theta) T) - 0)/9.81 ?

So I will take my initial height, L sin theta, and add it to (([sqrt (19.62(H-L*sin theta))] * sin theta) T), and subtract acceleration due to gravity (-4.9T^2). This I hope will give me h.

I understand what you are saying. I am trying to determine distance h (max height between stream of water and the ground). To do this would I add the vertical component of the water velocity ([sqrt (19.62(H-L*sin theta))] * sin theta) and the vertical component of the pipe L (L sin theta)? Am I...

Problem- I do not have a picture of the example so I will do my best to describe it. Water is in a large tank of depth H. On the side of tank, on the very bottom, an open ended pipe of length L leaves the tank at angle theta. The question asks to determine the maximum height of the water (h)...

Thank you for the help. I was able to determine the answer both algebraically and on my calculator

Hello, I am stuck on a math problem for one of my engineering courses which seems fairly straight forward, but I have had little success with. The problem reads as follows: The following data has the form y=ax^b. Estimate the coefficients a+b. Given data: Y X 1...