The equations mentioned at top, are they right?
I assume the sphere has a greater speed for a given h. Followed by the cylinder and the hoop. This is known by looking at the equations? Is that right?
Yea..it would.. :smile:
I understand that..it's just that I don't understand how...
the h is still the problem though..i still don't understand what tiny tim means by v=(dh/dt)/sin \theta
I can only manage to simplify the equations down to:
Sphere:
mgh=\frac{7}{10}mv2
Cylinder:
mgh=\frac{3}{4}mv2
Hoop:
mgh=mv2
Hiyya tiny-tim..we meet again..haha..
So sorry..but..i don't quite understand..the instantaneous velocity of point of contact?
Relationship?
w=v^2/r?
So sorry for the trouble and thank you so much for ur time and help.. :smile:
Homework Statement
Okay..here's d question:
A sphere, a cylinder and a hoop start from rest and roll down the same incline.
Determine which body reaches the bottom first.
Homework Equations
Sphere: I=2/5 mr2
Cylinder: I=1/2 mr2
Hoop: I= mr2
F=ma
The Attempt at a Solution
To find...
At first I don't think I fully understood..but now I get it..
Im1=m1x2
So..Im2 should b..
Im2=m2 (L-x)2
= m2 (L2+ x2 - 2xL)
Then as u said..by adding the Inertia's together..tadaa..the answer..Haha..
Big thank you to tiny-tim & chislam! :smile:
Take care you ppl!
Oh gosh.. -blush-
Dat simple?
Aiyo..I always complicate stuff...but..I still don't quite get it..haha..sorry ya..
So..okay..tryin out d simpler way..i get d 1st part which is I=(m1+m2)x^2 but wat about the rest of the answer where there is the +m2L^2 - 2m2xL?
And besides..i thought if it is...
Homework Statement
A system consists of two particles, of masses m1 and m2, is connected by a light rigid rod of length L.
a) Find the rotational inertia I of system for rotations of tis object about an axis perpendicular to the rod and distance x from m1
b) Show that I is a minimum when...