(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A system consists of two particles, of masses m1 and m2, is connected by a light rigid rod of length L.

a) Find the rotational inertiaIof system for rotations of tis object about an axis perpendicular to the rod and distance x from m1

b) Show that I is a minimum when x=x_{cm}

2. Relevant equations

I= I_{com}+ mh^{2}

I= 1/12 mr^{2}

3. The attempt at a solution

The answer provided was given as: I_{2}=(m1+m2)x^{2}+m2L^{2}-2m2xL

I understand that it is juz applyin the formula I= I_{com}+ mh^{2}but wat i do not understand is that

The thing that I dont understand is the mh^2 part..why is only m2 used in the equation?

And why when h= (L-x)^2 is expanded..what happens to the m2x^2?

And wat about the part b? By juz replacing the value it wif x...it juz doesnt make any sense...

Thanks ya..any help will be very much appreciated..

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Need help In Rotation Questions Please

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