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What is the Last Term in the Expression for \nabla\cdot(\phi\vec{A})?
Ok, so to start compute \nabla A which will just be (\frac{\partial}{\partial x}\vec{A},\frac{\partial}{\partial y}\vec{A},\frac{\partial}{\partial z}\vec{A}) You will end up with a scalar, which you can multiply by your scalar \phi and you should end up with xy^2z.- brew_guru
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- Forum: Calculus and Beyond Homework Help
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Legendre's Diff Eq using Frobenius
Homework Statement Show, by direct examination of the Frobenius series solution to Legendre's differential equation that; P_n(x) = \sum_{k=0}^{N} \frac{(-1)^k(2n-k)!} {2^n k! (n-k)! (n-2k)!}x^{n-2k} ;\ N=\frac{n}{2}\ \mathrm{n\ even,}\ N=\frac{n-1}{2}\ \mathrm{n\ odd} Write down the first...- brew_guru
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- Diff eq Frobenius
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- Forum: Calculus and Beyond Homework Help