Recent content by BrianSauce

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    Maximum work done in a Carnot Cycle

    This is the work I have done so far. I have established that W'/W = ln(V'B/Va)/ln(VB/VA) and I also found that the ratio of VC/VA = 16 using the pressure ratio. Points A, B, C, and D refer to the same points as 1, 2, 3, and 4 respectively.
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    Maximum work done in a Carnot Cycle

    The exact wording is that the Th is 4 times larger than Tc and the ratio of maximum to minimum pressure is 64, i.e. P1/P3 = 64.
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    Maximum work done in a Carnot Cycle

    I'm trying to show the ratio of W'/W where W' is the work done by a diatomic gas in one carnot cycle and W is the work done by a monatomic gas in one carnot cycle. Based on the above, shouldn't this ratio be 1? However I see in my textbook that this is 1/3.
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    Maximum work done in a Carnot Cycle

    Given that in a Carnot Cycle the two adiabatic processes are essentially equal and opposite in magnitude the total work done by the cycle is in the two isotherms. The total work of the system is generally given as -NR(Th-Tc)ln(Vb/Va). Does this mean that the work done by a monatomic ideal gas is...
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    Cylindrical barrel Hydrostatic Pressure

    Thank you for your help, to me finding center of masses for symmetrical objects seems a little more intuitive than what you did. However, for an object that isn't symmetrical I'll have to use your method. Either way thank you very much.
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    Cylindrical barrel Hydrostatic Pressure

    I understand the center of pressure part. Since this is a semicircle I could find the pressure at the center of mass and then just multiply it by the area. I will use this to solve it. I don't understand your integral though; where did 2h come from?
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    Cylindrical barrel Hydrostatic Pressure

    F=1/2πr2ρog∫0r-√r2-y2 ?
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    Cylindrical barrel Hydrostatic Pressure

    Homework Statement A circular cylindrical barrel is half full with oil. If the diameter of the base is 8.0 m, find the net force against each end if ρo = 800 kg/m3. The cylinder is on its side. Homework Equations F=P*A P=ρgdy The Attempt at a Solution P = ρo*g*h, where h is the radius which...
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    Solve "Energy with Friction Homework

    Ah I see now. For this instance I wanted a distance, and since distances are generally positive unless its displacement I added the square root. I got the correct answer! Thank you very much for your help. I have an exam in a few hours and you've helped put me at ease.
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    Solve "Energy with Friction Homework

    I'm currently doing that, the only problem I'm now having is that this isn't the first time I've had to apply the quadratic formula during homework or an exam and never know whether or not I'm supposed to use -b - √b2-4ac or -b + √b2-4ac
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    Solve "Energy with Friction Homework

    How should I go about solving for Δx? I get a weird polynomial where I get multiple answers for Δx. Should I set up some kind of work-Force relationship?
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    Solve "Energy with Friction Homework

    Homework Statement A 1.20 kg object slides to the left on a surface having a coefficient of friction of 0.250. The object has a speed of v_i = 3.00 m/s when it makes contact with a light spring that has a force constant of 60.0 N/m. The object comes to rest (briefly) after the spring has been...
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    Rolling without slipping force diagram

    Whoops, I meant delta x = 1/2at^2, no vi because it starts from rest.
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    Rolling without slipping force diagram

    My lab partner had helped me, he used the kinematic equation Vf = 1/2at^2 It completely slipped my mind. Thank you very much for the replies. :)
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