Ok, so using thiosulphate would it be:
2FeS_2O_3 \ + \ Cl_2 \ + \ -> \ 2Fe^{3+} \ + \ 2Cl^- \ + \ 2S_2O_3^{2-}
Using this, assuming that I want a titre of MnO4 (concentration say 0.020 mol/dm³) of say 0.015 dm³, then I calculate the mass of FeS_2O_3 to be about 33 grams... have I gone...