Recent content by brunettegurl

Ok Thanks I understand now ... I think what confused me when I was reading the explanation in my book was the implication that 2 different time values were to be used... Thank you :)

ohhh so for acceleration the vf would be 0 and vi would be +5 giving the acceleration of 10 .. correct? so then when we sub in the values in x=(5)(1)+ (0.50)(10)(1)^2 i still get an x(displacemnt) value of =10m and doubling this answer gives 20m do i continue to use 0.5 as my time value...

Im sorry how is it still 10 when you divide by time which is 0.5 now according to the explanation (1/2 the time) making the 10 now a 20 as acceleration

Hi I'm still a little confused my book states that to find distance we use half the total time in the equation w/acceleration and then solve for x by doubling the answer for total distance by doing this :: a=(5-(-5))/0.5= 20m/s^2 and when plugged into the equation x=(-5)(1)+...

Homework Statement A particle moving at 5m/s reverses its direction in 1 s to move at 5m/s in the opposite direction. If its acceleration is constant, what distance does it travel? Homework Equations x=volt+0.5at^2; a=(vf-vi)/t The Attempt at a Solution total time is 1s therefore...

#of nickels needed when only standard deviation is mentioned A previous study of nickels showed that the the standard deviation of the weight of nickels is 150 milligrams. A coin counter manufacturer wishes to find the 98% confidence interval for the average weight of a nickel. How many...

Hi 1) Suppose that it is known that in a certain large population,10%of is is colourblind. If a random sample of 25 people is drawn from the population, find the probability that exactly 8 of them are colourblind. My Take: is to use the Poisson Probability: f(x)= (e^-\lambda)* \lambda x/x...

Thanks!

1) A random sample of 2 people are selected from a group of 15 girls and 8 boys to participate in a study. Find the probability that the sample consists of 1 boy and 1 girl. My take : n=23 P(1girl)*P(1boy) (15/23)*(8/23) = 0.2268 the answer should be...

ok i got the answer but i have one question.. when i plug in the value of a why does it work without the negative sign?? ..thanks :))

so then this would be the correct equation \sumF=ma Ff-Fg=ma mu*mg*costheta-mgcostheta=ma mue= \frac{ma+mgsintheta}{mgcostheta} also does it make sense when finding the velocity to not do vcostheta ..??

coefficient of kinetic friction URGENT PLS. HELP! Homework Statement A box of mass 35 kg is sliding down a patch of frictionless snow inclined at 25deg to the horizontal with a speed of 6.0m/s when its a bare patch of dirt that's 1.50 m across.If the box's speed is reduced by 0.5m/s by the...

why would it be sin instead of cos??

so is my new equation wrong??

m1=3kg \frac{-Fg1+Ft}{m1}=a m1=5kg \frac{Fg2-Ft}{m2}=a i equated the two since the a would be the same to solve for Ft m2[(-m1*g*cos30deg)+T1]=m1[(m2*g*cos60deg]-T1] does that look better??