Recent content by Brute

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    Engineering Derivation of Source-Free RC circuit

    I would like to thank both of you and taking the time out to answer my question. It has made me understand the derivation thoroughly.
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    Engineering Derivation of Source-Free RC circuit

    Homework Statement Hi, If there is a series combination of a resistor and an initially charged capacitor, I know that the decay of the voltage is given by the equation v(t) = Ae^(-t/RC) where V(0) = A = V0. But i am unsure of how to get to this equations. Homework Equations If I assume...
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    Deriving the banked road angle with no friction

    OMG your a genius, it works perfectly. Thanks for the all the help man, this made me understand a lot of other problems too.
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    Deriving the banked road angle with no friction

    Ohh yeah I see it now so For forces in the x: mg sin x = mv^2/r cos x
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    Deriving the banked road angle with no friction

    Hopefully I go this right. For the forces in Y: Fn = mv^2/r sin X + mg cos X For forces in X: Fn Tan x = mv^2/ r cos x + mg sin x
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    Deriving the banked road angle with no friction

    Im so confused now, been working on it for over 2 hours almost in total. I'm assuming that there is a X and Y component of centripetal force that I don't understand, but I'm unsure of how I would draw it. I also realize that Fnet is equal to mv^2/r but I don't know what to do now. If you could...
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    Deriving the banked road angle with no friction

    Im not sure if I understand you correctly. But what i got is centripetal acceleration goes towards the circle, making it not the X-component of acc. But(assuming I understood right) it goes directly opposite the Fn force. So after I drew a new diagram I got: Fn = mv^2/r + mg cos x Fx = 0...
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    Deriving the banked road angle with no friction

    Homework Statement Derive the formula to calculate the angle at which the road should be banked to prevent the car from skidding(Ignore force of friction). Homework Equations tan x = v^2/gr ----- answer mv^2/r = fcThe Attempt at a Solution I get how they derived the formula due to this website...