Recent content by BTown

Don't over-think it. If the square tube that you have has a total height of 2 inches, then the value you are looking for would be half of that, which is 1 inch. Even if it wasn't a square tubing, but a rod for example (with a circle cross-section, as opposed to a square), it would still be...

Good point, a much more cost effective solution as well, especially considering the large variety of Al alloys out there now (prefer 6061 T6 myself, but not sure of how it performs when acting as a coating).

Exactly, and going back to your original post, the titanium effectively doesn't buy you anything except a few extra pounds, which is definitely something to be avoided for a racing vehicle. I wonder, would the opposite gain you anything (CF w/ Ti coating)? The titanium could offer...

I was referring to a composite with alternating meshes. Reading the initial post again, I realize that this is not what blixxa was referring to. Apologies... Nonetheless, I still would be a strong advocate of straight CF as you suggested, especially considering the application.

I agree with Mech_Engineer on using straight carbon fiber instead. carbo-titanium alloys have been around for a while, but are scarcely used because of their high cost and bonding problems. NASA did a study on this back in the 70's, but I am unsure what the results were. If you do decide...

No, we didn't go that in depth with our mesh. It was simply to optimize lift based on different dihedral angles and chamfer of the wing.

Travis pretty much covered it all. Depending on the program, you may take all of your math by the time you are a junior in college. Me for example, I went to Purdue University and I finished my last official math course at the end of my first semester as a Junior (Differential Equations...

metalworker, you got it man :) let me know if you have any more questions.

I just graduated in May 2011 from Purdue University and we had a few courses specifically on CFD. None of us understood what we were doing when it came to Fluent (except for the few people that read up like crazy on it and spent all their time in the lab), but on paper we all have "CFD...

metalworker, You're exactly right, you don't know the moment. However remember that moment is equal to force * distance, and you know force, it is the weight of the person. When I solved for x (which is the max distance the person can walk out before the beam yields), I was breaking moment...

I know you said no math, but it might help somebody else looking at this thread: 1. Find the material yield stress (google) 2. Set the material yield stress equal to the equation for bending stress, which is: σ = (M*y)/I , where: M = moment = force * distance y = distance from center to...