Recent content by bubblesarefun

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I understand it now! So the net force would be 12000N- m*g*sin(35) - 20N (frictional force). From there, we divide by mass to get the acceleration and the find the final velocity which in turn would be the launch velocity. Then I can use the Range= vi^2 /g * sin 2 theta to find the distance and...

Would I be closer with this one?

Sorry, gravity should not be at an angle.

Yes, but it is probably incorrect. I haven't gotten much of a handle on the angular free body diagrams.

Would the net force come from breaking 12000N into vectors and subtracting 20N from Fx (from the vector)? If so, the net force would be 9809.8N.

Yes, I realize that now which is why I broke the 12000N into vectors. Sorry, we didn't really go over the laws in class. We only got the formulas from it.

There are multiple forces (4), but the normal force and the force of gravity cancel out. There is the force exerted by the car which is 12000N and the force of friction which is 20N.

I'm not really sure what I am doing. Would I break down 12000N into vectors? Then sin(35)12000 would be Fy which would be added to Normal force to get Force of gravity. Then again, I probably got the normal force wrong. And cos(35)12000N would be Fx and I would subtract 20N from that. That would...

Hi, I have read the guidelines and have followed the rules to posting a question in the homework section. Thanks for your help! :)

Homework Statement Crash Test Craig drives his 800kg car up a 100m ramp that is at an angle of 35 degrees above the horizontal. The car exerts a forward force of 12000N and the force of friction between the ramp and the car is 20N. He is trying to jump over a series of spinning helicopter...

Hi, I'm Liza. I'm an 11th grade AP Physics student. I, however, am struggling to keep up as I have never taken physics previously so I'm hoping to get some homework help and also to learn new things. :)