Recent content by bullroar_86

ahh ok, that's pretty simple. the second part of the question is to find the values of each charge (they are equal but no value is given) I was trying to figure it out that way first. So I guess I draw the free body diagram first, find the electric force.. then plug the electric...

Ok i don't have the picture, but this should give you the idea. (the picture on the right) given: mass of each sphere = 5.0g length of each string = 40cm angle between the strings = 40 degrees (each sphere is 20 degrees from the vertical) due to repulsion the spheres each have the...

two spheres have the same negative charge. Each sphere is held by a string .4m long. the spheres hang with a 40 degree andgle between them due to repulsion What is the electrical force experienced by each sphere? in order to get the answer I need d (which I can get using trig), Q1 and...

How come we don't see light interference from two light sources? ex. two candles

what can be said about the work functions of two metals when the threshold wavelength in the photelectric effect increases. I'm having trouble finding and equation to describe this relationship. ANyone have any ideas?

Well the only thing I can come up with is what I already posted I'm thinking the "red = wavelength of 660 nm" only applies to air, and that figure varies with different mediums. So in different mediums the wavelength for red is different, so maybe in water its 470 nm, and it could be...

Unfortunately, I'm currently lacking in the "chick in a red bikini" dept. :biggrin: but my guess would be yes it is the same color.. I'm just not sure on the explanation

from my notes: red light has a wavelength of ~660 nm I just did a question where I was asked to find the wavelength in water.. I got an answer of 470 nm. Just curious why the color doesn't change. (a red bathing suit is still red under water) I'm thinking the "red = wavelength...

hmmmm...I have the same problem and I'm still having trouble with it. the incident angle (Θ1) can range anywhere from 1 degree to 89 degrees as it hits the glass, which would make the max Θ2 = 89 degrees which would make the smallest Θ3 = 1 degree but a critical angle of 1 degree...

well I'm still a little confused, the equation E = mgh is still a potential energy equation, not the kinetic energy equation (E = .5mv^2) is the above solution correct? (previous post)

one more spring question :smile: A block collides with a spring on a horizontal surface the block compresses the spring x metres from rest position. What was its speed at the instant of collision Ok so far I know how to do this question Ee = Ek .5kx^2 = .5mv^2 but in this...

ahh ok so, .2J = mgh and h = .2J/mg

well i know that the force of gravity will work against the kinetic energy... I have an elastic potential energy of .2 J, so the kinetic energy will also be .2 J (up) .. I know the mass of the item, and g, so I know that Fg = mg just not sure how to put the two together and get a...

if a vertical spring is being compressed down, is the Elastic potential energy the only energy? Ee = .5kx^2 is gravity included in that? or does it not play a role? and how could I tell how far an object would fly up in the air once the spring is released? thanks

Yeah I am hoping the final answer was just a miscalculation on their part. I've gone through the anwer step by step, and all the algebra looks good to me.