Recent content by bumblebeeliz

Thanks for your patience :)

Sorry, I meant this below: (scratch the first line) 97.989 x 1012 /2 48.969 x 1011 4.9 x 1012 (next time ill post the whole problem..sorry)

One more question: 1.95978 x 1012/ 0.02 97.989 x 1012 /2 48.969 x 1011 4.9 x 1012 Is this correct? So when you divide, the exponent drops?

Ah! Its all about the tricks for beginners. Much better :) = 19600 x 108 - 1.22x108 = 19598.7 x 108 or = 1.959878 x 1012

I see what you mean, but I am really not sure how to apply it in my situation. I basically factor it? I also saw this thread: https://www.physicsforums.com/showthread.php?t=100697 But for some reason it is really not clicking how I am supposed to apply it. I looked at some resources...

I thought we could subtract the exponent. I am not sure how to re-write the numbers and make them have the same exponent.

Homework Statement (1.4 x 106 m/s)2 - (3.5x104 m/s)2 Homework Equations The Attempt at a Solution We square them and then do we subtract them? Which would equal to: (1.4 x 106 m/s)2 - (3.5x104 m/s)2 (1.96 x 1012 m2/s2) - (1.22x108 m2/s2) (1.95878 x 104 m2/s2 ) Is this correct?

c2 = a2+b2 c (hyp) = 80-b sin0 = 40 / 80-b sin0 * 80 - 40 = b cos0 = b / 80-b cos0 * 80 /2 = b cos0 * 80 /2 = sin0 * 80 - 40 cos0 * 80 = sin0 * 80 - 40 * 2 cos0 / sin0 = 80-40 *2 / 80 tan0 = 1 0 = tan-1 1 0 = 45 degrees? I think I am having a lot of trouble with the trig. I...

Homework Statement A crate of eggs is located in the middle of the flatbed of a pickup truck. The truck is negotiating a curve in the road that may be considered as an arc of a circle of radius 35 m. If the coefficient of static friction between the flatbed and the crate is 0.66, with what...

Trig: I know I have a 90 degree angle and 40cm between A & C. But I can't seem to find the right formula. Are you talking about the c2=a2+b2? Or the sin0=opp/hyp? I am just having trouble putting the hypotenuse on the other side of the equation. Does it equal to: sin0 = 40cm / hyp hyp=...

Centripetal Force / Tension / Speed (HELP!) Homework Statement A 100 g bead is free to slide along an 80 cm long piece of string ABC. The ends of the string are attached to a vertical pole at A and C, which are 40 cm apart. When the pole is rotated about its axis, AB becomes horizontal...

so basically: f = 2.00s -1 = 0.500s. I think the extra zero's confused me.

Definitely easier to pull after it started sliding. Makes sense! Thanks.

Homework Statement A 150-g ball at the end of a string is revolving uniformly in a horizontal circle of radius 0.600m. The ball makes 2.00 revolutions in a second. What is the centripetal acceleration? Homework Equations T = 1/f v = 2\pir / T The Attempt at a Solution I know...

Sorry. I have trouble explaining physics. Ok, so basically it was a trick question because we actually do not need the \muk which is 0.51 for the toboggan?