Recent content by BurningHot

Hm... ok. I think I see what's happening now. Thank a lot for the help.

How did you end up with r = (x, sin(y), z)? If you take x and z to be the parameters, wouldn't y = cos-1√(x^2+z^2) ? When parameterizing a surface, you use two variables, right? With what I did, my surface ended up being parametrized as \vec{r}(x,y) = <x, y, \sqrt{cos^2y-x^2}>

Homework Statement Compute the integral \iint_S \sin y dS where S is part of the surface x^2 +z^2 = \cos^2(y) lying between the planes y=0 and y=\pi/2. Homework Equations \iint_S f(x,y,z) dS = \iint_D f(x,y, g(x,y)) \sqrt{g_x^2 +g_y^2 +1}dA \iint_S f(x,y,z) dS = \iint_D...