Recent content by Bwilli

Thanks a lot! I used avogadro's number. (13g)/(107.87g/mole)*(6.022E23atoms/mole)*(47electrons) = 3.41E24 electrons in the silver pin

Homework Statement (a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 13.0 g. Silver has 47 electrons per atom, and its molar mass is 107.87 g/mole. Homework Equations N/A The Attempt at a Solution I thought to try using the...