Recent content by c-murda
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Homework on quiz i took alredy
Since potential is a scalar, you can just add up the value and account for sign. I can see that for every positive charge at a fixed distance there is a corresponding negative charge. This is why when I add it up, the net potential is zero. So E=0 and V=0?- c-murda
- Post #9
- Forum: Introductory Physics Homework Help
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Homework on quiz i took alredy
are the two fields canceled by the push and pull of the oppositely charged particles...leading to 0- c-murda
- Post #7
- Forum: Introductory Physics Homework Help
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Homework on quiz i took alredy
i choose none of these are correct because none of them seemed correct to me. notic the 0% next to the last option(none of these are correct) the question is there in full. it was a multiple choise question.- c-murda
- Post #4
- Forum: Introductory Physics Homework Help
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Homework on quiz i took alredy
Homework Statement Charges +Q and –Q are arranged at the corners of a square as shown. When the electric field and the electric potential V are determined at P, the center of the square, we find that Homework Equations (+Q)---------------(-Q) -----------P-----------...- c-murda
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- Homework Quiz
- Replies: 9
- Forum: Introductory Physics Homework Help
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Phase difference b/w air-water interface and water-air interface
HA youre telling me...This is the 13 assignment I've had to do for this class all with 30+ questions...sig figs start to become a little annoying. Luckily they have improved the software side of the web-based homework(WEBASSIGN). with chem is was 2x as bad. Thank goodness there is a 1%...- c-murda
- Post #11
- Forum: Introductory Physics Homework Help
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Phase difference b/w air-water interface and water-air interface
which is correct!- c-murda
- Post #9
- Forum: Introductory Physics Homework Help
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Phase difference b/w air-water interface and water-air interface
I got: -π +2π(4.49) = 8.89π subtracting 7π leaves 1.98π = 6.22 radians- c-murda
- Post #8
- Forum: Introductory Physics Homework Help
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Phase difference b/w air-water interface and water-air interface
I know i thought long and hard about this and only have come up with these solutions repeatedly...is it possible they want a negative answer(which is my only guess left)? this is web based homework. The problem is from tipler 6th ed ch32 prob22 your right it doesn't seem likely but the...- c-murda
- Post #6
- Forum: Introductory Physics Homework Help
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Phase difference b/w air-water interface and water-air interface
Sorry typo...original problem was from the book... This is from my HW: Correct Problem Statement: Light of wavelength 592 nm is incident normally on a film of water 1.0 µm thick. The index of refraction of water is 1.33. then part b and c follow- c-murda
- Post #3
- Forum: Introductory Physics Homework Help
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Phase difference b/w air-water interface and water-air interface
Homework Statement Light of wavelength 418 nm is incident normally on a film of water 1.0 μm thick. The index of refraction of water is 1.33. (a) What is the wavelength of the light in the water? (b) How many wavelengths are contained in the distance 2t, where t is the thickness of the...- c-murda
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- Difference Interface Phase Phase difference
- Replies: 17
- Forum: Introductory Physics Homework Help
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Solving a Resistance-Inductance Circuit Problem
anyone?!?- c-murda
- Post #2
- Forum: Introductory Physics Homework Help
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Solving a Resistance-Inductance Circuit Problem
Homework Statement A coil of resistance 8.0 ohms and self-inductance 4.0 mH is suddenly connected across a constant potential difference of 100 V. Let t = 0 be the time of connection, at which the current is zero. Find the current I and its rate of change dI/dt at times (a) t = 0, (b) t = 0.1...- c-murda
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- Circuit
- Replies: 1
- Forum: Introductory Physics Homework Help
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Electric field inside a uniformly charged insulator
If a charge were distributed uniformly on the surface of the balloon(insulator). A point particle with charge q inside is greatest when it is anywhere inside the sphere because the force is zero? or when it is near the inside surface of the balloon?- c-murda
- Post #10
- Forum: Introductory Physics Homework Help
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Area of a Parallelogram with out cross products
i don't have mathematica that why i was checking my answer. and to know i could do it by hand. thanks!- c-murda
- Post #3
- Forum: Calculus and Beyond Homework Help
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Area of a Parallelogram with out cross products
Homework Statement given the vertices: (0,0) (3,1) (2,3) (5,4) Homework Equations solving without cross products and with mathematica if available The Attempt at a Solution Te1=[3] [1] Te2=[2] [3] [det[Ay]] ________ [det[A]] get you the solution...- c-murda
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- Area Cross Parallelogram
- Replies: 2
- Forum: Calculus and Beyond Homework Help