So would this be correct?
F = (m * A)
airDrag = .5 * Cd * FA * d * V * V
rollDrag = G * Cr * m
Propulsive force = F + airDrag + rollDrag
power at wheel = Propulsive force * V (what would the units be here; metric HP?)
power at engine = power at wheel * DL
Given the following instantaneous parameters and constants...
Known:
d = air density = 1.24
Cr = rolling resistance coeffecient = 0.015
FA = frontal area = 1.48
Cd = drag coefficient = 0.29F
G = gravity (mps2) = 9.80665
pi = 3.1415926
m = vehicle mass (Kg) = 1542
DL = drivetrain loss = .2
V...