Our continuous fraction starts at t[SIZE="1"]1...
So that t[SIZE="1"]1=k+1
so if k=0, the first value would be 1
but the thing is that all the others would also equal 1
There is only one undefined value for k, which is -1, since it gives dev by 0.
t[SIZE="1"]n is the nth value of the continued fraction.
t[SIZE="1"]n+1 is defined as:
t[SIZE="1"]n+1=k+(1/t[SIZE="1"]n)
The problem is that I don't know if k=0 gives an continuous fraction since it only gives one value for t[SIZE="1"]n, independent of the n value.
Hi there all smart people!
I'm doing some work on continued fractions of this type:
http://viitanen.se/cf.gif
I'w worked out an formula for the exact value of t[SIZE="1"]n and I'm now looking for limitations for that formula...
K≠-1 is one limitation since it will give dev. by 0.
My...
A inverse has to be reflected in the line Y=X and it has to pass the horizontal line test ie only have one possible x value for each y value??
How am I supposed to know if g meets the condition?
Hi there,
I have a math test tomorrow and I have some questions from our books review sets that I haven't been able to solve yet. For now I only have questions on functions and Sequenzes & Series but it's possible that I might ad a few more later during the day. Here it goes...
---Functions---...
Hi there,
superstrings are really interesting, but somewhat hard to understand.
There is a program by Nova called The elegant universe that explains it really well.
Here is the link to the site:
http://www.pbs.org/wgbh/nova/elegant/
And here is a direct link to where you can watch the...