diagonals run from the parabola y = - sqrt x to the parabola y = sqrt x.
the diagonal is the distance from y = - sqrt x to y = sqrt x
how is that not 2 sqrt x?
i honestly can't figure it out.
is there a formula to figure it out?
i need someone to explain to me where i am making a mistake because i am getting an answer that differs from that of the book.
the solid lies between planes perpendicular to the x-axis at x = 0 and x = 4. the cross-sections perpendicular to the axis on the interval 0 ≤ x ≤ 4 are squares...
ok... so after about 20 minutes of looking at it i realized that i completely made up the x^3 i don't know why or where it came from...
so is the answer:
sin(-x^4)2x - sin(-x^2)
please tell me that is right. i am about to go insane!
need help evaluating derivative of sin(x^2)
sorry I'm new to this site.
i tried substitution which did not get me anywhere.
next, i did taylor series but could not get an answer.
now i am stuck. i am almost positive i have to use a taylor series.
with the series i got
x^2 -...
calc 2 final tomorrow need urgent help!
Evaluate the derivative of the function
G(x) = ({integral} from x to x^2) of sin(-t^2)dt
this was on my review for the final and i just cannot get an answer. any help will be greatly appreciated.