Recent content by CaptainMarvel1899

When I was a student 60 years ago we were taught the Drude model but let's look at this free electron model. Nothing is true.Everything is permitted Evie Frye

Drude model also is correct for conductors.The depletion region isn't disappeared it get very narrow.

The B- ions are negatively charged so I ask if this will affect somehow.

Im a sure drude model is correct for all ohmic resistances and a diode has ohmic resistance even in forward bias.

Well I was just wondering how ohmic resistance works in a diode . I mean let's take forward bias mode.In forward bias mode electrons are diffused from the n type region to the p type region.The depletion layer still exists but is very narrow.So according to Drude model of ohmic resistance...

It is kind of the opposite.I know the voltage drop of the depletion regiin can be max 0.7V.If the energy whixh breaks the B- Si bonds is given by a 0.7V source then what would happen if we replaced it with a 10V source?

When we apply a forward voltage of 0.7V the depletion region becomes very narrow so the electrons have a big propability to be in the conduction band . Imagine what would happen with 10 volts.

If the electrons have a small propability of not being in the conduction band at 0.7V , then imagine what would be at 10V

Welcome

I am asking how the depletion region in a forward bias mode is tiny when thw breakdown voltage is 10V for example?

If we offer more energy than the bond energy , the bonds will be broken and electrons will start moving . That is my question.The net potential must be more than the bond energy(because the diode reaches equillibrium in reverse bias at 0.7V).What am I missing?

If there are no electrons in the p type region how is it negatively charged?

Moving electron holes are basicly electrons moving at the opposite direction and what this has to do with my issue?1

Nice one.

It has . Thats why some materials are solids in room temperature , some are liquids and some are gases.