Recent content by CaptGoodvibes
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C
Solving Series Expansion of Current in Resistor/Inductor Circuit
Ahhhhh... it's not 1-(...) it's 1-1(...) Dangit! I'm so caught up in the new stuff I forgot the details. Thanks so much!- CaptGoodvibes
- Post #6
- Forum: Calculus and Beyond Homework Help
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C
Solving Series Expansion of Current in Resistor/Inductor Circuit
It kills me when I try to get clever and my signs get skewed. So, now I've added a couple steps to insure I'm sign-correct and also added the third term to account for the 1's canceling. Here is the setup: I = 2.7 (1- \left( 1 +(-0.1) + \frac{(-0.1)^2}{2} + \frac{(-0.1)^3}{6}\right))...- CaptGoodvibes
- Post #4
- Forum: Calculus and Beyond Homework Help
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C
Solving Series Expansion of Current in Resistor/Inductor Circuit
Homework Statement A resistor and inductor are connected in series to a battery. The current in the circuit ( in A ) is given by I = 2.7(1-e-0.1), where t is the time since the circuit was closed. By using the series for ex, find the first three terms of the expansion of this function.Homework...- CaptGoodvibes
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- Circuit Current Expansion Series Series expansion
- Replies: 5
- Forum: Calculus and Beyond Homework Help