Recent content by Carrie233

Yes, P(A) is power set of A

Actually, I don't understand why {(1,3), (1,4), (2,3), (2,4)} cannot have the form of A1xB1. In my view, {(1,3), (1,4), (2,3), (2,4)} = {1,2} x {3,4} where {1,2} ∈ A1 and {3,4} ∈ B1.

Homework Statement Prove: If A and B each have at least two elements, then not every element of P(A×B) has the form A1 ×B1 for some A1 ∈ P(A)and B1 ∈ P(B). Homework EquationsThe Attempt at a Solution Suppose A = {1, 2}, B = {3, 4}. AXB = {(1,3), (1,4), (2,3), (2,4)} P(A) = {{1}, {2}, {1,2}...