Recent content by catmando

Homework Statement A rectangular sheet of thin material is rolled into a portion of a circular cylindrical surface of radius r. It rests under the action of gravity on a fixed cylindrical surface of radius R, symmetrical about the vertical centre line as shown below. If rolled slightly to...

yeah the question asked for that. thanks for you help :)

thanks i ended up getting I = mr^2 then using the parallel axis theorem I = Io + md^2 the moment of inertia about the centre of gravity is Io = mr^2 - md^2

bumpity

hello :D yeah i understand that, but when you have only a section of that cylindrical shell, if you integrate over r, won't that include the whole cylinder shell, not just a section? http://s13.postimage.org/90249nij9/picture.jpg if i integrated over r, wouldn't it include the rest of the...

thanks about the axis of the cylinder, I am really not sure i know how to find the moment of inertia about a complete cylinder but i really don't understand how to find the moment of inertia when its only a section of that cylinder, and the cylinder has a very small thickness. we are told that...

Homework Statement Find the moment of inertia of a circular thin cylindrical surface which ranges from -α/2 to α/2. So looks like - ) The dash being the origin. It basically looks like one fifth of a circular ring. Homework Equations I = mr² The Attempt at a Solution...