A child's pogo stick (Fig. P8.56) stores energy in a spring with a force constant of 2.50 104 N/m. At position A (xA = -0.120 m), the spring compression is a maximum and the child is momentarily at rest. At position B (xB = 0), the spring is relaxed and the child is moving upward. At position...
So, just because it is my last submission on this problem the answer should then be:
a = (9.8sin28) - (9.8 x .415 cos28)
such a stupid mistake...thanks
A child goes down a playground slide that is inclined at an angle of 28.0° below the horizontal. Find the acceleration of the child given that the coefficient of kinetic friction between the child and the slide is 0.415
Heres what I have so Far:
F - fk = ma
mgsin0 - MkN = ma
mgsin0 -...
So, when i posted my answer to the following equation
A hot-air balloon has just lifted off and is rising at the constant rate of 2.4 m/s. Suddenly one of the passengers realizes she has left her camera on the ground. A friend picks it up and tosses it straight upward. If the passenger is 1.4 m...
Cepheid,
Thank you for your responses. The exact question for your first reply was:
A car is behind a truck going 30.0 m/s on the highway. The driver looks for an opportunity to pass, guessing that his car can accelerate at 2.7 m/s2, and he gauges that he has to cover the 16.0 m length of...
Oh, I see now. Thanks so much for the help.
If you do not mind, I have another two questions that I would really appreciate someone answering if they had the time.
A hot-air balloon has just lifted off and is rising at the constant rate of 2.4 m/s. Suddenly one of the passengers...
A ball is thrown upward from the top of a 25.4-m-tall building. The ball's initial speed is 12 m/s. At the same instant, a person is running on the ground at a distance of 32.0 m from the building. What must be the average speed of the person if he is to catch the ball at the bottom of the...
Oh!
Maybe got it now:
So the equation would be:
Displacement = (initial velocity)t + .5 at^2
Therefore,
Displacement = 0 + .5(9.8)(.25)
The .25 representing the time the ball had to fall.
So that would make the answer, 1.225 meters.
Thanks you so much for your help hage567. If you wouldn't...
So, this could be way off, if it has a velocity of zero at the top, then the ball would fall at an acceleration rate of 9.8 m/s^2 since only gravity would be acting on it? So would that mean that the maximum height would be just 9.8 x .95 since that was the amount of time that the ball was able...
Hmm..they way i understood the problem, the ball is only being tossed once in the air, and passes the wire after .70 s then passes it again .50 s later (1.2). This would mean that the ball was at its peak at .95 s
I could be totally wrong though...this problem just is not clicking with me
Homework Statement
To find the height of an overhead power line, you throw a ball straight upward. The ball passes the line on the way up after 0.70 s, and passes it again on the way down 1.2 s after it was tossed
What is the height of the power line?
m
What is the initial speed of...