Recent content by Ceeerson

oh ok well i won't have that option for a while so is there a recommended book for beginners over vector calc, it doesn't have to be dumbed down, just interpret-able any insight would be greatly appreciated!

i just have the final displacement in the x direction, i was just guessing that since the launch starts and ends on the ground that half the time wouldd be at max height, neglecting air reistance

will someone give me an explanation of the process of integration of a vector with respect to another vector. the reason i ask is because in the topic of electricity i am discussing the electric flux of a point charge inside a solid surface. I know that the dot product is related, and i can even...

ok so I am going to start this problem over. ok so in the y direction, Δy = (vsinθ)t - (1/2)gt^2; Vf = Vsinθ - gt; vf^2 = v^2sinθ^2 - 2gΔy in x direction, Δx = Vcosθt so I am guessing i rearrange for t using the x equation, so t = Δx/v(cosθ) then i plug it into the first equation...

and (usinθ)/2g = Δy

Δx = utcos(θ), Δy = ut/2sin(θ) - 1/2g(t/2)^2 Δx = 152.4m

and yes, θ is launch angle above the horizontal

oh, Δy indicates the maximum height achieved by the ball, which is achieved at half the total time since the balls starting y position is negligible, Δx indicates the total distance covered in the x position of the coordinate system, so making the ball's starting position the origin, the...

sorry the equation in the bottom is tangent of thetaθ, I'm not sure what you are asking, they are both dependent on time, assuming gravity is constant, apparently one is able to derive an equation and calculate max height using only the three kinematic equations.but the only known variables are...

deriving equation for minimum height in projectile motion with two give me's :) Homework Statement A ball is launched at a 45 degree angle and lands 152.4 m away. What is the maximum height the ball will reach during its flight. I Know the answer, what I need is to find a way to derive an...