Recent content by Chelsea S

Oh neat! Thanks!

Hey Thanks for the reply! It gets me pointed in the right direction, at least. I can't believe I never even though to pick up my Q.M book... because Astrophysics has nothing to do with things moving the speed of light *sarcasm* Thanks for the help! I appreciate it!

1.Well this isn't a specific homework problem, I just need a quick idea to use for a paper. Our linear algebra professor is giving us a 50 point paper project/report that has to do with the applications of linear algebra in the field of study we have chosen to pursue. I would like to do...

Oh, alight. On the inside I'm a little sad. I was half expecting the physical meaning to be something odd and hard to grasp; like figuring out how many times you'd have to throw a baseball at a wall before it tunneled through, just something odd.

So, beyond that it has not permutation symmetry (which, yes that is odd), does it make E14 special? Is there something particular about that energy state that makes it have those particular triples?

I think you should be able to... that's exactly is what degeneracy is, right? Finding similar energy states for different wave functions. So I think it would still count as degeneracy even though your values for m and n (in your example) are different. Like: (3,3,3) = 27... and (5,1,1) would...

Oh. Wow I was making that way too difficult. I.. don't even know why I didn't think of it that way. Geeze. Well thanks for clarifying! hehe. I guess I should stop studying Q.M at 4 in the morning.

Alright, I'm back with yet another question... So the prof was explaining that the energy in an infinite cubical well is E((h2∏2)/2ma2))(nx2+ny2+nz2) Which is all well and good, and he gave us the example of: ψ1,2,1 = E = 6((h2∏2)/2ma2)) And with little explanation mixed it up once...

That is totally what I thought! I asked him if there was a reason why the two together just didn't make a 'separate' observable, and he was like "Yeah I'm not sure if it does." I said, "well do they have an effect on each other when they're multiplied together?" he said "I'll have to look it up...

Oh, okay that makes sense! So... you CAN just pull out <AB> as if it were a single operator... And, yes, this was a professor. Thanks for the reply, I was seriously going to use a whole notebook worth of paper trying to figure out the way he did it XD

Okay.. so these are exactly my notes. Let my operator be A (since I don't have a 'hat' to put on top of it), with eigenvalue A σA=√(<(ΔA)2>) σA2 =<(ΔA)2> σA2 = Ʃ((ΔA)2(P(A)) σA2 =Ʃ(A-<A>)2(P(A)) σA2 = <(A-<A>)ψ|(A-<A>)ψ> Define f = (A-<A>)ψ So, σA2 = <f|f> Similarly, we will do...

Alright... So I'm in an 'introductory' Q.M class in college right now, it's the only one that this two-year college has, so I don't have an upper division Q.M Profs to talk to about this, and since my prof is equally confused, I turn to the internet. Okay, so everyone knows that <ψ|Aψ> = <a>...