Recent content by Chowie

Hmm, I have the hamiltonian written down here as \hat{H}=-\frac{\bar{h}^{2}}{2m}∂^{2}/∂x^{2} So that is also equal to i\bar{h}∂/∂t ? \vec{}

Is it total energy for a free particle?

Homework Statement What physical quantity is represented by the operator i\bar{h}∂/∂t Homework Equations i\bar{h}∂/∂t The Attempt at a Solution It's a one mark question, I just have no idea what it is and I can't find it in my notes D:.

Hello there, I'm making a presentation on the speed of sound in a few days and I was wondering if anyone knows where I can find a video that shows a (preferably huge) explosion from a distance with a timer on it. What I wish to convey from this video is the fact that the light from the...

It was pretty much this, turns out I had missed out the 2 in the final answer as it just didn't seem to go there, but it is necessary for the solution to be simplified in that way. Thanks a bunch for all the support y'all have shown, much appreciated.

Yeah I was approaching this all wrong, I looked at the method on wikipedia a few days ago and it worked out fine, thanks for the input.

it seems the solution given is just confusing, as the 2s should cancel but they have both been written in. There needs to be that extra 2 there for the simplification to be valid, what we have written does not simplify to what we once had. If that makes any sense.

I don't think it is, I haven't received any emails about it so I doubt so. My friend is working on the same piece at the moment so we'll see if he gets the same apparent error as us and then I'll start thinking it could be a typo.

I used the identity: \frac{1}{i}(e^{i\omega\tau}-e^{-i\omega\tau}) = 2 sin(\omega \tau) instead of the one you provided because it seemed to just cut out dealing with cosine terms altogether. this left me with: F(\omega) = \frac{2A\tau}{\sqrt{\omega\tau}} (...

I can't seem to find the edit button so I've corrected my slashes in this post: F(\omega) = \frac{A}{i \omega \sqrt{2\pi}}(e^{2 i \omega \tau}-e^{-2 i \omega \tau}) + \frac{A}{i \omega \sqrt{2\pi}}(e^{i \omega \tau}-e^{- i \omega \tau})

I have a very similar result generic; except that my i's are on the denominator (which is just as mathematically sound as your result) The identity given to me for transforming exponentials into sine functions is: sin(A) = \frac{1}{2i}(e^{iA}-e^{-iA}) I'm just trying to work out how to...

Ah ok, so splitting it into 2 signals isn't immediately simpler as I have to find f(t) from -2tau to 0 but once I have this function and I have applied the F.T to it, it's symmetric and therefore simpler? hmm... I'm going to work on the more obvious method of 3 transforms as I don't know what...

Wait I'm confused, LCKurtz says break into 3 but Dickfore says break it into 2 signals? I've already broken it into three signals and I'm working on that, unless you can expand on your reason as to why that's a bad idea.

That's what I have written down on my page right now pretty much, except my i's are negative. I get the first integral in the second equation you've written to be = \frac{A}{i\omega}(e^{2i\omega\tau} - e^{i\omega\tau} Do you think this is correct? I can't see a way to reduce that to a sine...

Homework Statement Homework Equations The Attempt at a Solution To be perfectly honest I have not attempted a solution thus far, my knowledge of the Fourier transform is quite limited at the moment. I understand that I can use the above equation but what I want to know is if I...