I reasoned that (x-1)/x is always less than 1 for positive x. Therefore it will tend to zero as the exponent tends to infinity. But what is confusing is that when working it out for 1 to 100, the value increases.
Is the the limit 0?, and when does the limit "turn".
Ok, thanks a lot for your help. I'm doing revision for my physics (got exams coming up). Thanks again for your help. Looking over the work again, I can see how much I still need to study. I haven't given my physics nearly enough time this year.
Acceleration would be: 156/40= 1.4m.s^-2
Then the height from the ground would be: sin30(40) = 20m.
Vf^2 = (3)^2 + 2(1.4)(20)
Vf^2 = Sqrt(65)
= 8.062m.s^-2
Is that correct?
Sorry: *edit:
Well, I think I kind of got it. To get acceleration: (392N)(sin30) - (40) = Fnet. When I do this, I get an net force of 156 and an acceleration of 3.9m.s^-2?? Is that right??
So there's gravity, friction and the kinetic energy from the start? How exactly would I calculate this?
I understand that it'll slow it down, but how exactly would I do this calculation? Surely the friction will reduce the acceleration? How do I calculate the acceleration experienced by the...
Sorry about the typo - just fixed it. I still don't completely understand the question "What is the net force experienced by the sled parallel to the angle?" I'm having a mental block on this one for some reason. How does the frictional force effect the speed at the bottom of the slope?
Homework Statement
A sled is going down a slope of 40m, which has an angle of 30 degrees with the horizontal. The total mass of the sled is 40kg. There is a constant frictional force of 40 N holding back the movement of the sled. The sled has an initial velocity of 3m.s-1. What is the net force...