I used the drag force divided by the weight force, and then took the inverse sin of the answer.
Θ = sin-1 ((drag force)/(mg))
Unfortunately i can't explain y i used this as that will require me to do a diagram which i find time consuming, and as I'm short on time i can't help it SORRY !
Hey lok sorry for the late reply i did work it out last night. just been busy and haven't been able to put it up i will in an hour or 2 though thanks for the help.
hey lok i presume we are talking about the kinematics equations. I will have a look back and report to you in a min but i don't see how i can get the angle using those equations.
actually its late in NZ so imma c this tomorrow but i think i got it, just need to manipulate the equations properly.
A fully loaded Cessna-182 airplane of mass 1260 kg has an engine failure when flying with an airspeed of 126 km/h at an altitude of 2870 m on a calm day. It then glides at a constant glide angle (which is the direction of flight below the horizontal) towards a safe landing at this constant speed...
ty arildno and born2bwire i get it now, and thanks to born2bwire i get my equation is incorrect. Also ty born2bwire for the simple check.
after going through the trig a hundred times i figured i was looking at the wrong triangle a simple rookie mistake. I ty legends for your time the maths...
i understand what u guys are telling me but when i try to derive that equation that is what i get maybe this should be in maths not in physics. ill review my working, and MAYBE talk to the lecturer
at any rate ty for your time guys i really appreciate it
its hard to find good help at...
Hi guys,
I am currently studying a basic college physics course at a university in New Zealand.
The course is only going over what we were taught in college so far. I came across a practice problem and was unsure how to go about solving it. So I looked up my lecturers online notes and I...