I got one answ... I(0.224) = 1.2*(1 - e^-2) = 1.038 A
::::
5 + 5*10/(5 + 10) = 8.33
30/8.33 = 3.6 A
5*10/(5 + 10)=3.33
3.33*3.6 = 12 V
12/10 = 1.2 A
so I have that now how would I find the current in the switch at that same
time?
pic : http://s982.photobucket.com/albums/ae310/christianerik/?action=view¤t=untitled.jpg
If the switch is closed at t = 0, find the
current in the inductor at t = 0.224 s. Answer
in units of A.
&
Find the current in the switch at that same
time.
I know that i must use i = V/R(1 -...
If the switch is closed at t = 0, find the
current in the inductor at t = 0.224 s. Answer
in units of A.
&
Find the current in the switch at that same
time.
I know that i must use i = V/R(1 - e^-t/L/R) but can't seem to get the right answer.
Any help is appreciated...5 ohms...
A 31 m length of coaxial cable has a solid
cylindrical wire inner conductor with a di-
ameter of 2.042 mm and carries a charge of
7.32 μC. The surrounding conductor is a
cylindrical shell and has an inner diameter of
6.748 mm and a charge of −7.32 μC.
Assume the region between the...
At t=0 the switch S is closed with the capacitor is uncharged.
..... 3M ohm... 102 micro F
--------------^^^^^--------ll-------------
l l
l ... s...<----i--->......l
l-------l i-------/.--------------------------l
17...
For a long period of time the switch S is
in position “b”. At t = 0 s, the switch S is
moved from position “b” to position “a”.
....3 M ohm
l---------------^^^^^^-----------------l
l........…......l
l...1 M ohm...4micro F.....l b
l---^^^^^^^^^-------------ll---------/ i...