I went back to the basics and started with the kinetic formula. Xf=x+Vot+1/2at^2... I used Vf=Vo+at solved for t...plugged that into kinematic equation.
Now I have Xf=1/2a(Vf/a) ^2 solved for a. Then plugged that into...meu k(mgcos(theta))-(mgsin(theta))=ma but I have two variables. This is...
But in the formula I reach...the masses just can't cancel? I'm sorry, I'm not quite understanding. I get your analogy, but still confused on how it pertains to a frictional problem.
A flatbed truck slowly tilts its bed upwards to dispose of a crate. When the tilt angle is 16 degrees or above the create begins to slide. When the create reaches the bottom of the flatbed, it has slide 2.85 meters, its speed is 2.71 m/s.
I found meu static by summing the forces in both the x...
Homework Statement
I know incline is 16 degrees
I know distance traveled is 2.85 meters
I know Vf is 2.71 meters/second I calculated the meu static and got .287
Homework EquationsThe Attempt at a Solution
Tried every thing so lost