Recent content by CioCio

  1. C

    Waves in Semiclosed Tubes: Calculating Frequencies and Lengths

    Thanks, Aleph. You're right; I was making it too complicated. :approve: For closed tubes, ƒn = nƒ1 So, in response to your question: ƒ2 = 2f, ƒ3 = 3f, ƒ4 = 4f, and so on. With the 400 Hz difference between successive frequencies, and knowing that even harmonics are skipped in...
  2. C

    Waves in Semiclosed Tubes: Calculating Frequencies and Lengths

    I'm doing a self-guidance type of study, trying to learn my way through a book based on physics and the sound of music. I haven't dabbled with waves since high school. I know that these are sequential harmonics. Therefore, given that it's a semiclosed tube and L = length of tube in meters...
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