Recent content by cjkent

Got it now great! For some reason when I tried this earlier I got t and t' muddled in the time dilation equation so then when I progressed I got (v^4)/(c^2) + v^2 etc and couldn't solve it. My final answer came to be 0.92c which seems reasonable and checks out fine. Thanks for being patient...

Yep sorry as I was tryng to edit on my last post I did that giving v=L/(t'γ) but then γ=1/ √(1−(v^2 /c^2)) which is dependant on v Thanks again for the help. I hope this isn't just me being incredibly dense.

t= t'γ Edit: and then I subbed that into v=L/t giving v=L/(t'γ) but then γ=1/ √(1−(v^2 /c^2))

Thanks so much guys for the speedy replies. Is that not just v=L/T where the L and T were both measured in the Earth frame? (forgive the notation I'm trying to be consistent with those in the other equations) @chestermiller But I don't have Δt do I? Only the time as measured on the...

Homework Statement A spaceship travels from Earth to the vicinity of the star that is measured by astronomers on Earth to be six light-years away. The spaceship and its occupants have a total rest mass of 32 000 kg. Assume that the spaceship travels at constant velocity. The time taken as...