Recent content by cleverfield

Unfortunately no. For the equation with just one wire i have: B=u/2pi*I/xfor the second wire it would be B=u/2pi*I/d-xEven if this is right, I am not sure where to go next.

I know the expression is B=u/2pi * I/r ----- It is r that I have the problem with. How do you know r when it can vary from between 0 and d. where d is the max.

thanks for the reply. I know Amperes and vector, and maybe I'm not thinking this through properly. I know the direction of the magnetic fields. But how do you come up with a formula that is based on a variable "x" that could be any distance between the two currents?

Homework Statement Let two long parallel wires, a distance d apart, carry equal currents I in the same direction. One wire is a x=0 and the other is a x=d. Determine B along the x-axis between the wires as a function of X. Repeat problem if wire at x=0 is 2I and in the opposed direction...

Which equation?

Homework Statement The drag force on large objects such as cars, planes, and sky divers moving through air is more nearly Fdrag = -bv^2. For this quadratic dependence on v, determine a formula for the terminal velocity vTerm, of a vertically falling object. Express your answer in terms...

Unfortunately that answer is not accepted by my online workbook. Thanks for your efforts, I'll take this one into the prof to find out more. I don't expect u to work so hard on one questions. Thanks!

I do not understand. T - 0.30(N) - mgsin51 = 2.5a T is in the direction of the pulley so it is positive Friction is in the opposite direction of the acceleration so it is negative mg according to my coordinate system would also have negative x,y components. I am not sure which...

Thats what I used in my original work. I took the mgcos51 and found that friction = 0.30(mgcos51) then I used that when determining F=MA in the x direction: T - (friction force) - x component of mg = ma T - 0.30(N) - mgsin51 = 2.5a I then solved for T with the other box...

Isnt the normal force just mg(cos51) for the first box?' If not please explain why.

Homework Statement Two masses M1 = 2.5kg and M2 = 4.0kg are on inclines and are connected together by a string . The coefficient of kinetic friction between each mass and its incline is Uk = 0.30. If moves up, and moves down, determine their acceleration. Homework Equations...

Homework Statement The terminal velocity of a 3×10−5kg raindrop is about 5m/s . Assuming a drag force , and Drag Force = -bv 1. Assuming a drag force determine the value of the constant . 2. Assuming a drag force determine the time required for such a drop, starting from rest, to reach 63%...