Your cos and sin are wrong, you have them mixed up. Cos is for stuff dealing with "x" and sine is for stuff dealing with "y" (for this problem).
try it as Ex = E1cos37, and Ey=E1sin37.
All your reasoning is correct, just a simple mistake.
Method 1 of yours looks more right. Pi = Pf
therefore, (miA*viA) + (miB*viB) = (mfA*vfA)+(mfB*vfB)
Your only unknown is vfB
Just make sure your initial signs are all correct, that's when drawing a diagram helps.
Yes, you do have to.
If truck A is going 10m/s to the right (positive), Truck B is going 3 m/s to the left (negative), or -3m/s. Since the question stated they are going towards each other.
Its best to draw a picture, then label the diagram with a direction you've decided to call "positive"...
Im not very good at typing in the formulas. But the 1/2 comes from the derivation of the expression you are using, and the properties of calculus.
x=xo+Vot +1/2at2
is derived from v=dx/dt, separate the dx and dt (v*dt=dx) and integrate both sides. You can subsitute v for (vo +at), since you...
For part b you know ω, A, and x. You should be able to solve for and find t.
I guess one way to solve "b" is by using your equation(i), you can find speed and acceleration by taking the 1st and 2nd derivative wrt t.
Homework Statement
We were told that it is a simple algebraic substitution to derive the t' expression from the x and x' equations for a lorentz transformation. However, I keep reaching a dead end in the algebra.
Homework Equations
x=B(x'+vt')
x'=B(x-vt)
B=1/(Sqrt(1-(v/c)^2))
B^2 = c^2/(c^2...
You know ω initial and ω final, and Δθ. You can solve for angular acceleration using one of the kinematics equations for constant acceleration. Once you have alpha you can solve for t.
Max Static friction is given by (μs*normal force), normal force in your diagram is "A" so set O=A and solve for μs. Looks good, up until the end. You have 1699.14/981 flipped, should be 981/1699.14. However its best to solve the problem in variables first and then plug in your values at the end...
Homework Statement
An astronaut on a distant planet drops a rock from the top of a cliff and observes it takes 2.532s to hit the base of the cliff. Then takes a 2nd rock and throws it straight up with a speed of 17.81m/s so that it reaches a height "h" above the cliff before falling to the base...